Project Euler Problem 18
The idea for the solution below came from Stackoverflow. Working from "bottom to top", *data* is reversed in function problem18.
(defparameter *data*
'((75)
(95 64)
(17 47 82)
(18 35 87 10)
(20 04 82 47 65)
(19 01 23 75 03 34)
(88 02 77 73 07 63 67)
(99 65 04 28 06 16 70 92)
(41 41 26 56 83 40 80 70 33)
(41 48 72 33 47 32 37 16 94 29)
(53 71 44 65 25 43 91 52 97 51 14)
(70 11 33 28 77 73 17 78 39 68 17 57)
(91 71 52 38 17 14 91 43 58 50 27 29 48)
(63 66 04 68 89 53 67 30 73 16 69 87 40 31)
(04 62 98 27 23 09 70 98 73 93 38 53 60 04 23)))
(defun bottom-up-max (a b)
(mapcar #'max
(mapcar #'+ a b)
(mapcar #'+ (rest a) b)))
(defun problem18 (lst)
(first (reduce #'bottom-up-max (reverse lst))))
To get the solution, evaluate:
(problem18 *data*)
The idea for the solution below came from Stackoverflow. Working from "bottom to top", *data* is reversed in function problem18.
(defparameter *data*
'((75)
(95 64)
(17 47 82)
(18 35 87 10)
(20 04 82 47 65)
(19 01 23 75 03 34)
(88 02 77 73 07 63 67)
(99 65 04 28 06 16 70 92)
(41 41 26 56 83 40 80 70 33)
(41 48 72 33 47 32 37 16 94 29)
(53 71 44 65 25 43 91 52 97 51 14)
(70 11 33 28 77 73 17 78 39 68 17 57)
(91 71 52 38 17 14 91 43 58 50 27 29 48)
(63 66 04 68 89 53 67 30 73 16 69 87 40 31)
(04 62 98 27 23 09 70 98 73 93 38 53 60 04 23)))
(defun bottom-up-max (a b)
(mapcar #'max
(mapcar #'+ a b)
(mapcar #'+ (rest a) b)))
(defun problem18 (lst)
(first (reduce #'bottom-up-max (reverse lst))))
To get the solution, evaluate:
(problem18 *data*)
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